Further syntax errors in source code
There are some instances of !== in the code. I take it they should be just !=
Anthony M.
July 27,
Maybe not. != is "not equal to," "!==" is the strict inequality operator, which tests to see if instances are the same. It's the opposite of "===", which is the strict equality operator.
So for example, given a = 5 and b = 5, a == b, but a !== b, because a and b don't point to the same instance of a variable.
July 27,
Wrong; in your example, (a !== b) is false (or conversly, a === b).
The ECMAScript spec says:
11.9.6 The Strict Equality Comparison Algorithm
The comparison x === y, where x and y are values, produces true or false. Such a comparison is performed as follows:
1.If Type(x) is different from Type(y), return false.
2.If Type(x) is Undefined, return true.
3.If Type(x) is Null, return true.
4.If Type(x) is not Number, go to step 11.
5.If x is NaN, return false.
6.If y is NaN, return false.
7.If x is the same number value as y, return true.
8.If x is +0 and y is -0, return true.
9.If x is -0 and y is +0, return true.
10. Return false.
11.If Type(x) is String, then return true if x and y are exactly the same sequence of characters (same length and same characters in corresponding positions); otherwise, return false.
12. If Type(x) is Boolean, return true if x and y are both true or both false; otherwise, return false.
13.Return true if x and y refer to the same object or if they refer to objects joined to each other (see 13.1.2). Otherwise, return false.
July 27,